Use C/C++ to achieve small box games

Results demonstrate

Realize the function

As shown above. Key control pig movement, push the box to reach the destination.

1. First of all, we need to save boxes, pigs and other information, and add multiple maps using 3d arrays.

2. Define the values of pigs, boxes, walls, empty Spaces and other information in the 3D array.

Empty lot 0 Wall 1 Destination 2 box 3 pigs 4 2+4=6 Pigs arrived at destination also shows pig box arrived at destination 2+3=5Copy the code

3. Press the button to push the box.

Consider multiple scenarios:

①. The movement of the pig (open space, aim at)

②. Piggy pushing boxes (open space, destination)

Store map information in 3D arrays: HERE I have made only two kinds of graphs, which can be added by yourself

Int backgrand [MAP] [ROW] [COL] = / / MAP figure {{1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 2, 0, 0, 1, 1, 1, 0, 0, 3, 1, 1, 1, 1, 2, 3, 0, 4, 0, 0, 1, 1, 0, 1, 0, 3, 3, 2, 1, 1, 1, 0, 3, 2, 0, 0, 1, 1, 0, 0, 2, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1}, {0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 2, 0, 0, 0, 1, 1, 1, 0, 0, 3, 0, 1, 1, 1, 2, 3, 0, 4, 0, 0, 1, 1, 0, 1, 0, 0, 0, 1, 1, 1, 1, 0, 3, 2, 3, 0, 1, 1, 0, 0, 0, 0, 2, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1}};Copy the code

Drawing using easyX library, loading image and drawing window only use three statements: very simple

initgraph(); // Draw window size loadimage(); // load image putinmage(); // Release the imageCopy the code

Specific can see the code!

The code block

#include<stdio.h>
#include<Windows.h>
#include<stdlib.h>
#include<time.h>
#include<conio.h>
#include<graphics.h>
#define ROW 8
#define COL 8
#define MAP 2//map个可以自己添加数


int count = 0;//哪个map图
/*
空地             0
墙	              1
目的地           2
箱子             3
猪               4  2+4=6 猪到达目的地也显示猪
箱子到达目的地   2+3=5


*/


IMAGE image1, image2, image3, image4, image5, image6;

int backgrand[MAP][ROW][COL] =//map图
{
	{
		1, 1, 1, 1, 1, 1, 1, 1,
		1, 0, 0, 0, 2, 0, 0, 1,
		1, 1, 0, 0, 3, 1, 1, 1,
		1, 2, 3, 0, 4, 0, 0, 1,
		1, 0, 1, 0, 3, 3, 2, 1,
		1, 1, 0, 3, 2, 0, 0, 1,
		1, 0, 0, 2, 0, 0, 1, 1,
		1, 1, 1, 1, 1, 1, 1, 1
	},
	{
		0, 1, 1, 1, 1, 1, 1, 1,
		1, 1, 0, 2, 0, 0, 0, 1,
		1, 1, 0, 0, 3, 0, 1, 1,
		1, 2, 3, 0, 4, 0, 0, 1,
		1, 0, 1, 0, 0, 0, 1, 1,
		1, 1, 0, 3, 2, 3, 0, 1,
		1, 0, 0, 0, 0, 2, 0, 1,
		1, 1, 1, 1, 1, 1, 1, 1
	},
};
int Judge(){//p判断是否结束一局
	int i = 0;
	for (i = 0; i < ROW; i++){
		int j = 0;
		for (j = 0; j < COL; j++){
			if (backgrand[count][i][j] == 3 || backgrand[count][i][j] == 2){//判断是否还有箱子或者目的地
				return 0;
			}
		}
	}
	return 1;
}

void Backgrand(){//绘制地图
	int i = 0;
	for (; i < ROW; i++){
		int j = 0;
		for (; j < COL; j++){
			int x = 80 * j;//横轴是y(列)，数轴是x（行）。
			int y = 80 * i;
			switch (backgrand[count][i][j]){
			case 0:
				putimage(x, y, &image3);
				break;
			case 1:
				putimage(x, y, &image1);
				break;
			case 2:
				putimage(x, y, &image6);
				break;
			case 3:
				putimage(x, y, &image4);
				break;
			case 4:
			case 6:
				putimage(x, y, &image2);
				break;
			case 5:
				putimage(x, y, &image5);
				break;
			default:
				break;
			}
		}
	}
}

void Keymove(){//按键控制猪的运动
	int i = 0;
	int j = 0;//j定义出来了，里面for循环要初始化
	for (i = 0; i < ROW; i++){ //找到猪的坐标
		for (j = 0; j < COL; j++){
			if (backgrand[count][i][j] == 4 || backgrand[count][i][j] == 6){
				break;
			}
		}
		if (backgrand[count][i][j] == 4 || backgrand[count][i][j] == 6){
			break;
		}
	}
	char key = _getch();//获得按键
	switch (key){
	case 'w':
	case 'W':
	case 72:
		if (backgrand[count][i - 1][j] == 0 ||\
			backgrand[count][i - 1][j] == 2)
		{  
			backgrand[count][i][j] = backgrand[count][i][j] - 4;//猪运动，猪旁边是空地或者是目的地
			backgrand[count][i - 1][j] = backgrand[count][i - 1][j] + 4;
		}
		if (backgrand[count][i - 1][j] == 3 && (backgrand[count][i - 2][j] == 0 || \
			backgrand[count][i - 2][j] == 2))   //猪推箱子运动条件，猪旁边是箱子与上箱子旁边是空地。
		{                                       //后面或的条件要括号括起来
			backgrand[count][i][j] = backgrand[count][i][j] - 4;                                      
			backgrand[count][i - 1][j] = backgrand[count][i - 1][j] + 4;
			backgrand[count][i - 1][j] -= 3;
			backgrand[count][i - 2][j] += 3;
		}
		if (backgrand[count][i - 1][j] == 5 &&\
			backgrand[count][i - 2][j] == 0)  //箱子到达目的地，后面还有空的情况
		{
			backgrand[count][i][j] -= 4;
			backgrand[count][i - 1][j] += 4;
			backgrand[count][i - 1][j] -= 3;
			backgrand[count][i - 2][j] += 3;
		}
		break;
	case 's':
	case 'S':
	case 80:
		if (backgrand[count][i + 1][j] == 0 || \
			backgrand[count][i + 1][j] == 2)
		{  //猪运动
			backgrand[count][i][j] = backgrand[count][i][j] - 4;
			backgrand[count][i + 1][j] = backgrand[count][i + 1][j] + 4;
		}
		if (backgrand[count][i + 1][j] == 3 && (backgrand[count][i + 2][j] == 0 ||\
			backgrand[count][i + 2][j] == 2))
		{
			backgrand[count][i][j] = backgrand[count][i][j] - 4;
			backgrand[count][i + 1][j] = backgrand[count][i + 1][j] + 4;
			backgrand[count][i + 1][j] -= 3;
			backgrand[count][i + 2][j] += 3;
		}
		if (backgrand[count][i + 1][j] == 5 && \
			backgrand[count][i + 2][j] == 0)
		{
			backgrand[count][i][j] -= 4;
			backgrand[count][i + 1][j] += 4;
			backgrand[count][i + 1][j] -= 3;
			backgrand[count][i + 2][j] += 3;
		}
		break;
	case 'a':
	case 'A':
	case 75:
		if (backgrand[count][i][j - 1] == 0 || \
			backgrand[count][i][j - 1] == 2)
		{  //猪运动
			backgrand[count][i][j] = backgrand[count][i][j] - 4;
			backgrand[count][i][j - 1] = backgrand[count][i][j - 1] + 4;
		}
		if (backgrand[count][i][j - 1] == 3 &&\
			(backgrand[count][i][j - 2] == 0 ||\
			backgrand[count][i][j - 2] == 2))
		{
			backgrand[count][i][j] = backgrand[count][i][j] - 4;
			backgrand[count][i][j - 1] = backgrand[count][i][j - 1] + 4;
			backgrand[count][i][j - 1] -= 3;
			backgrand[count][i][j - 2] += 3;
		}
		if (backgrand[count][i][j - 1] == 5 && \
			backgrand[count][i][j - 2] == 0)
		{
			backgrand[count][i][j] -= 4;
			backgrand[count][i][j - 1] += 4;
			backgrand[count][i][j - 1] -= 3;
			backgrand[count][i][j - 2] += 3;
		}
		break;
	case 'd':
	case 'D':
	case 77:
		if (backgrand[count][i][j + 1] == 0 || \
			backgrand[count][i][j + 1] == 2)
		{  //猪运动
			backgrand[count][i][j] = backgrand[count][i][j] - 4;
			backgrand[count][i][j + 1] = backgrand[count][i][j + 1] + 4;
		}
		if (backgrand[count][i][j + 1] == 3 && (backgrand[count][i][j + 2] == 0 ||\
			backgrand[count][i][j + 2] == 2))
		{
			backgrand[count][i][j] -= 4;
			backgrand[count][i][j + 1] += 4;
			backgrand[count][i][j + 1] -= 3;
			backgrand[count][i][j + 2] += 3;
		}
		if (backgrand[count][i][j + 1] == 5 && backgrand[count][i][j + 2] == 0){
			backgrand[count][i][j] -= 4;
			backgrand[count][i][j + 1] += 4;
			backgrand[count][i][j + 1] -= 3;
			backgrand[count][i][j + 2] += 3;
		}
		break;
	default:
		break;
	}


}


void Initgraph(){
	initgraph(80 * ROW, 80 * COL);
	loadimage(&image1, "1.jpg");//墙
	loadimage(&image2, "2.jpg");//猪
	loadimage(&image3, "3.jpg");//空地
	loadimage(&image4, "4.jpg");//箱子
	loadimage(&image6, "6.jpg");//目的地
	loadimage(&image5, "5.jpg");//箱子到目的地
}




int main(){
	Initgraph();
	while (1){
		Backgrand();
		Keymove();
		if (Judge()){
			Backgrand();
			Sleep(500);
			count++;
		}
		if (count == MAP){
			break;
		}
	}


	getchar();
	closegraph();
	system("pause");
	return 0;
}

Copy the code

Then this one push box game is OK!