describe

Select * from employees;

Select * from employees where emp_no = odd and last_name = Mary from employees where emp_no = odd and last_name = Mary from employees where emp_no = odd and last_name = Mary from employees where emp_no = odd and last_name = Mary from employees where emp_no = odd and last_name = Mary from employees where emp_no = odd and last_name = Mary

Example 1

drop table if exists  `employees` ; 
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
INSERT INTO employees VALUES(10001,'1953-09-02','Georgi','Facello','M','1986-06-26');
INSERT INTO employees VALUES(10002,'1964-06-02','Bezalel','Simmel','F','1985-11-21');
INSERT INTO employees VALUES(10003,'1959-12-03','Bezalel','Mary','M','1986-08-28');
INSERT INTO employees VALUES(10004,'1954-05-01','Chirstian','Koblick','M','1986-12-01');
INSERT INTO employees VALUES(10005,'1953-11-07','Mary','Sluis','F','1990-01-22');

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The output

10005|1953-11-07|Mary|Sluis|F|1990-01-22
10001|1953-09-02|Georgi|Facello|M|1986-06-26

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My answer

select * from employees where emp_no % 2 = 1 and last_name ! = 'Mary' order by hire_date desc;Copy the code