Work encountered a requirement to change its state for the "distance" from the specified time to the current time. This requirement is done out, packaged, can be used to pass the parameter. /*create By suji 2018-09-07*/ / determine what day of the week is returnedfunction week(dayNum){
switch(dayNum){
case 7:
return 'day';
break;
case 1:
return '一';
break;
case 2:
return '二';
break;
case 3:
return '三';
break;
case 4:
return 'four';
break;
case 5:
return 'five';
break;
case 6:
return '六';
break; }} // Timestamp format parameter time: the specified time, nowtime: the current timefunctiontimeTo(time,nowtime) { var date = new Date(time); var nowdate =new Date(nowtime); var PY = date.getFullYear(); Var NY = nowdate.getFullYear(); Var Y = date.getFullYear() +'/';
var M = (date.getMonth()+1 < 10 ? '0'+(date.getMonth()+1) : date.getMonth()+1) + '/';
var D = date.getDate() + ' ';
var h = date.getHours() + '/';
var m = date.getMinutes() + '/';
var s = date.getSeconds();
if(PY==NY){// Check whether the year is the same, yes output format 08/01 if not 2018/08/01return M+D;
}
else{
returnY+M+D; }} // Convert the timestamp to the same time xxxx-xx-xx 00:00:00function timeTotime(time) {
var date = new Date(time);
var Y = date.getFullYear() + The '-';
var M = (date.getMonth()+1 < 10 ? '0'+(date.getMonth()+1) : date.getMonth()+1) + The '-';
var D = date.getDate() + ' ';
var h = 00 + ':';
var m = 00 + ':';
var s = 00;
var newtime= Y+M+D+h+m+s;
returnnew Date(newtime).getTime(); If it is the same day, today is displayed; if it is less than one day, yesterday is displayed; if it is more than two days, the day of the week is displayed; if it is more than one week, the day of the week is displayed; if it is more than one week, the day of the week is displayed; if it is more than one week, the day of the week is displayed. Tomorrow, the day after, // same thing next week.ifDate(1536600501000); / / the refsfunction ifDate(perDate){
var date = new Date().getTime();//获取当前时间时间戳
var date = timeTotime(date);//对时间戳进行转化，转化成时间统一xxxx-xx-xx 00:00:00
var perDate =timeTotime(perDate);
console.log(date,perDate);
var runTime =(date-perDate)/1000;
var year = Math.floor(runTime / 86400 / 365);
runTime = runTime % (86400 * 365);
var month = Math.floor(runTime / 86400 / 30);
runTime = runTime % (86400 * 30);
var day = Math.floor(runTime / 86400);
var day =parseInt(day);//获取相差的天数，可以为负数
console.log(day);
var nowday = new Date(date).getDay();//获取当前时间是星期几，0-6
if(nowday==0){// If 0, set Sunday to 7. }if(day==0){
console.log('today');
}
else if(day==1){
console.log('yesterday');
}
else if(day==2){
console.log('the day before yesterday);
}
else if(day==-1){
console.log('tomorrow');
}
else if(day==-2){
console.log('the day after tomorrow');
}
else ifConsole. log(day,nowday); (day>2&&day<nowday){console.log(day,nowday); var dayNum =nowday-day; console.log('week'+(week(dayNum)));
}
else if(day>2&&day>=nowday&&day<nowday+7){var dayNum=7- math.abs ((nowday-day)); console.log('last week'+(week(dayNum)));
}
else if(day>= nowDay +7){console.log(timeTo(perDate,date))}else if(math.abs (day)<(7-nowday)&&day<0){var dayNum = math.abs (day)+nowday; console.log('week'+(week(dayNum)));
}
else if(Math.abs(day)>(7-nowday)&&Math.abs(day)<(7-nowday+7)&&day<0){ var dayNum=Math.abs(day)+nowday-7; // Check whether it is next week console.log('next week'+(week(dayNum)));
}
else if(math.abs (day)>(7-nowday+7)&&day<0){// Check whether the next week is over, display the normal format console.log(timeTo(perDate,date)); }}Copy the codeThis function feels more practical, we can take useful to use, of course, may need to optimize, but also ask the gods to change their own manual change.